x^2-17x+25=0

Solution for x^2-17x+25=0 equation:

x^2-17x+25=0

a = 1; b = -17; c = +25;
Δ = b2-4ac
Δ = -172-4·1·25
Δ = 189
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{189}=\sqrt{9*21}=\sqrt{9}*\sqrt{21}=3\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-3\sqrt{21}}{2*1}=\frac{17-3\sqrt{21}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+3\sqrt{21}}{2*1}=\frac{17+3\sqrt{21}}{2}
$